C Program to Display Armstrong Numbers Between 1 and 1000 - Loop Through Range

Display Armstrong Numbers from 1 to 1000

#include <stdio.h>

int main() {
    int number, originalNumber, remainder, result;

    printf("Armstrong numbers between 1 and 1000 are:\n");

    for (number = 1; number <= 1000; ++number) {
        originalNumber = number;
        result = 0;

        // Compute the sum of cubes of digits
        while (originalNumber != 0) {
            remainder = originalNumber % 10;
            result += remainder * remainder * remainder;
            originalNumber /= 10;
        }

        // Check if the number is an Armstrong number
        if (result == number) {
            printf("%d\n", number);
        }
    }

    return 0;
}

Armstrong numbers between 1 and 1000 are:
1
153
370
371
407
        

Practice: Armstrong Range

This program iterates through the numbers from 1 to 1000, computes the sum of the cubes of the digits for each number, and prints the number if the sum matches the original. Only a few three‑digit numbers satisfy this property (153, 370, 371 and 407).